64/x^2-16+1=2x/x-4

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Solution for 64/x^2-16+1=2x/x-4 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

64/(x^2)-16+1 = (2*x)/x-4 // - (2*x)/x-4

64/(x^2)-((2*x)/x)-16+1+4 = 0

64/(x^2)-16-2+1+4 = 0

64*x^-2 = 13 // : 64

x^-2 = 13/64

-2 < 0

1/(x^2) = 13/64 // * x^2

1 = 13/64*x^2 // : 13/64

64/13 = x^2

x^2 = 64/13 // ^ 1/2

abs(x) = (64/13)^(1/2)

x = (64/13)^(1/2) or x = -(64/13)^(1/2)

x in { (64/13)^(1/2), -(64/13)^(1/2) }

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